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In , the mole fraction or molar fraction, also called mole proportion or molar proportion, is a quantity defined as the between the amount of a constituent substance, ni (expressed in unit of moles, symbol mol), and the total amount of all constituents in a mixture, ntot (also expressed in moles):

x_i = \frac{n_i}{n_\mathrm{tot}}
It is denoted xi (lowercase letter x), sometimes (lowercase letter chi).
(2025). 9780547125329, Cengage Learning.
(2025). 9780470587119, Wiley.
(For mixtures of gases, the letter y is recommended.)

It is a dimensionless quantity with dimension of \mathsf{N}/\mathsf{N} and dimensionless unit of moles per mole ( mol/mol or molmol−1) or simply 1; may also be used (e.g., nmol/mol for ). When expressed in , it is known as the mole percent or molar percentage (unit symbol %, sometimes "mol%", equivalent to cmol/mol for ). The mole fraction is called amount fraction by the International Union of Pure and Applied Chemistry (IUPAC) and amount-of-substance fraction by the U.S. National Institute of Standards and Technology (NIST). This nomenclature is part of the International System of Quantities (ISQ), as standardized in ISO 80000-9, which deprecates "mole fraction" based on the unacceptability of mixing information with units when expressing the values of quantities.

The sum of all the mole fractions in a mixture is equal to 1:

\sum_{i=1}^{N} n_i = n_\mathrm{tot} ; \ \sum_{i=1}^{N} x_i = 1
Mole fraction is numerically identical to the number fraction, which is defined as the number of particles () of a constituent Ni divided by the total number of all molecules Ntot. Whereas mole fraction is a ratio of amounts to amounts (in units of moles per moles), molar concentration is a quotient of amount to volume (in units of moles per litre). Other ways of expressing the composition of a mixture as a dimensionless quantity are mass fraction and .


Properties
Mole fraction is used very frequently in the construction of . It has a number of advantages:
  • it is not temperature dependent (as is molar concentration) and does not require knowledge of the densities of the phase(s) involved
  • a mixture of known mole fraction can be prepared by weighing off the appropriate masses of the constituents
  • the measure is symmetric: in the mole fractions x = 0.1 and x = 0.9, the roles of 'solvent' and 'solute' are reversed.
  • In a mixture of , the mole fraction can be expressed as the ratio of to total of the mixture
  • In a ternary mixture one can express mole fractions of a component as functions of other components mole fraction and binary mole ratios:
  • : \begin{align}
 x_1 &= \frac{1 - x_2}{1 + \frac{x_3}{x_1}} \\[2pt]
 x_3 &= \frac{1 - x_2}{1 + \frac{x_1}{x_3}}
     
\end{align}

Differential quotients can be formed at constant ratios like those above:

\left(\frac{\partial x_1}{\partial x_2}\right)_{\frac{x_1}{x_3}} = -\frac{x_1}{1 - x_2}

or

\left(\frac{\partial x_3}{\partial x_2}\right)_{\frac{x_1}{x_3}} = -\frac{x_3}{1 - x_2}

The ratios X, Y, and Z of mole fractions can be written for ternary and multicomponent systems:

\begin{align}
 X &= \frac{x_3}{x_1 + x_3} \\[2pt]
 Y &= \frac{x_3}{x_2 + x_3} \\[2pt]
 Z &= \frac{x_2}{x_1 + x_2}
     
\end{align}

These can be used for solving PDEs like:

 \left(\frac{\partial\mu_2}{\partial n_1}\right)_{n_2, n_3} =
 \left(\frac{\partial\mu_1}{\partial n_2}\right)_{n_1, n_3}
     

or

 \left(\frac{\partial\mu_2}{\partial n_1}\right)_{n_2, n_3, n_4, \ldots, n_i} =
 \left(\frac{\partial\mu_1}{\partial n_2}\right)_{n_1, n_3, n_4, \ldots, n_i}
     

This equality can be rearranged to have differential quotient of mole amounts or fractions on one side.

  \left(\frac{\partial\mu_2}{\partial\mu_1}\right)_{n_2, n_3} =
 -\left(\frac{\partial n_1}{\partial n_2}\right)_{\mu_1, n_3} =
 -\left(\frac{\partial x_1}{\partial x_2}\right)_{\mu_1, n_3}
     

or

  \left(\frac{\partial\mu_2}{\partial\mu_1}\right)_{n_2, n_3, n_4, \ldots, n_i} =
 -\left(\frac{\partial n_1}{\partial n_2}\right)_{\mu_1, n_2, n_4, \ldots, n_i}
     

Mole amounts can be eliminated by forming ratios:

 \left(\frac{\partial n_1}\right)_{n_3} =
 \left(\frac{\partial\frac{n_1}{n_3}}{\partial\frac{n_2}{n_3}}\right)_{n_3} =
 \left(\frac{\partial\frac{x_1}{x_3}}{\partial\frac{x_2}{x_3}}\right)_{n_3}
     

Thus the ratio of chemical potentials becomes:

  \left(\frac{\partial\mu_2}{\partial\mu_1}\right)_{\frac{n_2}{n_3}} =
 -\left(\frac{\partial\frac{x_1}{x_3}}{\partial\frac{x_2}{x_3}}\right)_{\mu_1}
     

Similarly the ratio for the multicomponents system becomes

  \left(\frac{\partial\mu_2}{\partial\mu_1}\right)_{\frac{n_2}{n_3}, \frac{n_3}{n_4}, \ldots, \frac{n_{i-1}}{n_i}} =
 -\left(\frac{\partial\frac{x_1}{x_3}}{\partial\frac{x_2}{x_3}}\right)_{\mu_1, \frac{n_3}{n_4}, \ldots, \frac{n_{i-1}}{n_i}}
     


Related quantities

Mass fraction
The mass fraction wi can be calculated using the formula
w_i = x_i \frac{M_i}{\bar{M}} = x_i \frac {M_i}{\sum_j x_j M_j}

where Mi is the molar mass of the component i and is the average of the mixture.


Molar mixing ratio
The mixing of two pure components can be expressed introducing the amount or molar of them r_n = \frac{n_2}{n_1}. Then the mole fractions of the components will be:
\begin{align}
 x_1 &= \frac{1}{1 + r_n} \\[2pt]
 x_2 &= \frac{r_n}{1 + r_n}
     
\end{align}

The amount ratio equals the ratio of mole fractions of components:

\frac{n_2}{n_1} = \frac{x_2}{x_1}

due to division of both numerator and denominator by the sum of molar amounts of components. This property has consequences for representations of using, for instance, .


Mixing binary mixtures with a common component to form ternary mixtures
Mixing binary mixtures with a common component gives a ternary mixture with certain mixing ratios between the three components. These mixing ratios from the ternary and the corresponding mole fractions of the ternary mixture x1(123), x2(123), x3(123) can be expressed as a function of several mixing ratios involved, the mixing ratios between the components of the binary mixtures and the mixing ratio of the binary mixtures to form the ternary one.
x_{1(123)} = \frac{n_{(12)} x_{1(12)} + n_{13} x_{1(13)}}{n_{(12)} + n_{(13)}}


Mole percentage
Multiplying mole fraction by 100 gives the mole percentage, also referred as amount/amount percent abbreviated.


Mass concentration
The conversion to and from mass concentration ρi is given by:
\begin{align}
                    x_i &= \frac{\rho_i}{\rho} \frac{\bar{M}}{M_i} \\[3pt]
 \Leftrightarrow \rho_i &= x_i \rho \frac{M_i}{\bar{M}}
     
\end{align}

where is the average molar mass of the mixture.


Molar concentration
The conversion to molar concentration ci is given by:
\begin{align}
 c_i &= x_i c \\[3pt]
     &= \frac{x_i\rho}{\bar{M}} = \frac{x_i\rho}{\sum_j x_j M_j}
     
\end{align}

where is the average molar mass of the solution, c is the total molar concentration and ρ is the of the solution.


Mass and molar mass
The mole fraction can be calculated from the mi and Mi of the components:
x_i = \frac{\frac{m_i}{M_i}}{\sum_j \frac{m_j}{M_j}}


Spatial variation and gradient
In a mixture, the mole fraction triggers the phenomenon of .

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